GRE Graduate Record Examination Test: Verbal, Quantitative, Analytical Writing GRE Test Dumps in PDF

Free GRE GRE Test Real Questions (page: 7)



Let Q, R, and S be positive integers such that S is a factor of Q and R. Let



Which of the following is equal to ?

  1. |q - r|2
  2. |(q - r)(S)|2
  3. |q2 - r2|
  4. |(q2 - r2)(S)|
  5. |(q2 - r2)(S2)|

Answer(s): D

Explanation:

We are given that S is a factor of both Q and R, meaning that we can express Q and R in terms of S as:
Q = qS

R = rS

where q and r are integers.
We need to simplify the given expression:



Since Q = qS and R = rS,



S(q2 - r2), or |(q2 - r2)(S)|



The integer p is a prime number greater than 5, and 5 is a factor of p +p2.
What is the remainder when p is divided by 5?

  1. 0
  2. 1
  3. 2
  4. 3
  5. 4

Answer(s): E

Explanation:

We can express p + p2 as:
p + p2 = p(1 + p)
The problem states that 5 is a factor of p + p2, which means:
p(1 + p) 0 (mod 5)
This implies that p(1 + p) is divisible by 5. Since p is a prime number greater than 5, p is not divisible by 5.
Therefore, the factor of 5 must come from 1 + p.
We know that 1 + p must be divisible by 5. Thus, we have:
1 + p 0 (mod 5)
p -1 (mod 5)
Since -1 4 (mod 5), we conclude that:
p 4 (mod 5)



If n is an odd integer, which of the following must be an even integer?



  1. n + 2
  2. n2 + 3
  3. n2 + 2n

Answer(s): D

Explanation:

· Since n is odd, n - 1 is even. Dividing an even number by 2 results in an integer, but it could be odd or even depending on n.
· Since n is odd, n + 1 is even. Dividing an even number by 2 results in an integer, but it could be odd or even depending on n.
· Since n is odd, adding 2 results in an odd number.
· Since n is odd, squaring it keeps it odd, meaning n2 is odd. Adding 3 to an odd number results in an even number. This must be even.
· Since n is odd, n2 is odd. Since n is odd, multiplying it by 2 results in an even number. Adding an odd number (n2) and an even number (2n) results in an odd number.



If 0 < r < t and r = 50 - t, what is the greatest possible value of the median of r, t, and 28?

  1. 23
  2. 24
  3. 26
  4. 28
  5. 29

Answer(s): D

Explanation:

Since r = 50 - t, we substitute it into the inequality 0 < r < t:
1. 0 < 50 - t, which simplifies to t < 50.
2. 50 - t < t, which simplifies to
50 < 2t
25 < t
So, the range of t is 25 < t < 50.
The median is the middle number when r, t, and 28 are arranged in increasing order.
Since r = 50 - t, we note that r decreases as t increases.
Case 1: If t < 28
r = 50 - t would be greater than 28 because t is small.

The numbers in order are t, 28, r.

The median is 28.

Case 2: If t > 28
r = 50 - t would be less than 28 because t is large.

The numbers in order are r, 28, t.

The median is still 28.

From both cases, the median is always 28, regardless of the values of t and r.
The greatest possible value of the median is 28.



It costs d dollars to buy n nails. At this rate, what is the cost of n + 1,850 nails, in dollars?






Answer(s): E

Explanation:





Based on the information given, which of the following pairs of energy sources accounted for more than one- half of the world primary energy supply? (Choose all that apply.)

  1. Coal and oil
  2. Natural gas and oil
  3. Natural gas and nuclear power
  4. Natural gas and renewable sources

Answer(s): A,B

Explanation:

We sum the percentages for each pair:
· Coal and Oil: 24.4 + 34.4 = 58.8% More than 50%
· Natural Gas and Oil: 21.2 + 34.4 = 55.6% More than 50%
· Natural Gas and Nuclear Power: 21.2 + 6.5 = 27.7% Less than 50% · Natural Gas and Renewable Sources: 21.2 + 13.5 = 34.7% Less than 50%





What fraction of the world primary energy supply was from hydroelectric power or natural gas?






Answer(s): C

Explanation:





If the region representing nuclear power is a sector of a circle with radius x, which of the following is equal to the area of the sector?

  1. 0.065x2
  2. 0.0652x2
  3. 6.5x2
  4. (360)(0.0652)x2

Answer(s): E

Explanation:

According the formula for the area of a sector and since nuclear power represents 6.5% of total energy:



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