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GRE GRE Test Exam (page: 8)
GRE Graduate Record Examination Test: Verbal, Quantitative, Analytical Writing
Updated on: 15-Feb-2026

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GRE Test PDF with 793 Questions

QUESTION: 57

Note: Projections were made in the year 2000.

Approximately what is the projected average freshwater supply per person for the United States, in cubic feet? (1 cubic meter approximately equals 35.31 cubic feet.)

200
1,200
2,600
160,000
260,000

Answer(s): E

Explanation:

The average freshwater supply per person for the United States is 7.5 × 1000 = 7500 cubic meters.
Now, convert this to cubic feet using the conversion factor 1 cubic meter = 35.31 cubic feet:
7500 × 35.31 = 264,825 cubic feet
The calculated value is approximately 264,825 cubic feet, which is closest to 260,000 cubic feet.

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QUESTION: 58

Note: Projections were made in the year 2000.

The total freshwater supply projected for Mexico is approximately 30 times greater than the total freshwater supply projected for which country?

China
Egypt
Malawi
Tunisia
United Kingdom

Answer(s): C

Explanation:

To determine the total freshwater supply projected for each country, we need to consider both the population and the average freshwater supply per person.
Mexico has a population of 100 million and an average freshwater supply of approximately 2.5 thousand cubic meters per person. The total freshwater supply for Mexico is:
100 million × 2.5 thousand cubic meter = 250 million cubic meters Next, we need to find the country whose total freshwater supply is approximately 30 times smaller than Mexico's.

Find the total freshwater supply for each country:

· China: Population 1,400 million, average freshwater supply 2.0 thousand cubic meters per person.
1,400 × 2.0 = 2800million cubic meters (that is greater than Mexico's) · Egypt: Population 100 million, average freshwater supply 0.5 thousand cubic meters per person.
100 × 0.5 = 50million cubic meters (that is 5 times smaller than Mexico's) · Malawi: Population 10 million, average freshwater supply 1.0 thousand cubic meters per person.
10 × 1.0 = 10million cubic meters (that is 25 times smaller than Mexico's) · Tunisia: Population 10 million, average freshwater supply 0.5 thousand cubic meters per person.
10 × 0.5 = 5million cubic meters (that is 50 times smaller than Mexico's) · United Kingdom: Population 60 million, average freshwater supply 1.0 thousand cubic meters per person.
60 × 1.0 = 60million cubic meters (that is 4 times smaller than Mexico's)

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QUESTION: 59

Note: Projections were made in the year 2000.

The average freshwater supply per person for the United States is projected to decrease 20 percent from 1997 to 2025. Based on the data, which of the following was closest to the average freshwater supply per person for the United States in 1997, in cubic meters?

6,000
8,200
8,800
9,400
9,900

Answer(s): D

Explanation:

From the chart, the average freshwater supply per person for the United States in 2025 is approximately 7.5 thousand cubic meters.
Given that the average freshwater supply per person for the United States is projected to decrease by 20% from 1997 to 2025, we can calculate the average freshwater supply per person for 1997.
Let x be the average freshwater supply per person in 1997. The supply is projected to decrease by 20%, so the average freshwater supply in 2025 is 80% of the value in 1997.
0.80 × x = 7.5

The value of x is approximately 9.375 thousand cubic meters, which is closest to 9,400 cubic meters.

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QUESTION: 60

In year Y, if the number of United States households was approximately 96 million and if 0.4 percent of the United States households that used oil as a type of heating were in City C, approximately how many households in City C used oil as a type of heating?

50,300
384,000
503,040
5,030,400
38,400,000

Answer(s): A

Explanation:

To find the number of households in City C that used oil as a type of heating, follow these steps:
1. First, calculate the number of households in the United States using oil for heating:
Households using oil = 96 million × 13.1% = 96,000,000 × 0.131 = 12,576,000
2. Next, calculate 0.4% of these households to find how many are in City C:
Households in City C = 12,576,000 × 0.004 = 50,304
So, approximately 50,300 households in City C used oil as a type of heating.

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QUESTION: 61

The average (arithmetic mean) of the numbers of households that used oil and wood as types of heating was approximately what percent of the average of the numbers of households that used the remaining 6 types of heating?

18%
22%
54%
66%
82%

Answer(s): D

Explanation:

To solve this problem, we need to compute the average number of households that used oil and wood as types of heating, and compare it to the average of the remaining 6 types of heating.
Total number of households = 96 million.

Households using oil = 96,000,000 × 13.1% = 12,576,000

Households using wood = 96,000,000 × 5.0% = 4,800,000

Households using the remaining 6 types of heating are:

- Natural Gas = 96,000,000 × 51.3% = 49,248,000
- Electricity = 96,000,000 × 24.8% = 23,808,000
- Liquefied Gas = 96,000,000 × 4.0% = 3,840,000
- Kerosene = 96,000,000 × 1.2% = 1,152,000
- Coal = 96,000,000 × 0.4% = 384,000
- Solar Power = 96,000,000 × 0.2% = 192,000
The average of households using oil and wood is calculated as follows:

The average of households using the remaining 6 types of heating is calculated as follows:

Now, we compare the average of households using oil and wood to the average of the remaining 6 types:

This is approximately 66% of the average of the remaining 6 types of heating.

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QUESTION: 62

FILL BLANK

The number of United States households in year Z was 1.6 percent greater than that in year Y. If 0.9 percent of

United States households in year Z used kerosene as a type of heating, then the number of households that used kerosene as a type of heating in year Z was what percent of the number of households that used kerosene as a type of heating in year Y?

Give your answer to the nearest whole percent. (Enter your answer as an integer or a decimal in the answer box. Backspace to erase.)

76

Answer(s): A

Explanation:

We know the total number of households in year Y is 96 million, based on the previous information.

From the table, we know that 1.2% of U.S. households in year Y used kerosene as a type of heating.

The number of households using kerosene in year Y is:

96,000,000 × 1.2% = 96,000,000 × 0.012 = 1,152,000 households.

We are told that the number of households in year Z is 1.6% greater than in year Y. Therefore, the total number of households in year Z is:

96,000,000 × (1 + 1.6%) = 96,000,000 × 1.016 = 97,536,000 households.

We are also told that 0.9% of the U.S. households in year Z used kerosene as a type of heating. The number of households using kerosene in year Z is:

97,536,000 × 0.9% = 97,536,000 × 0.009 = 877,824 households.

To find what percent the number of households using kerosene in year Z is of the number in year Y, we divide the number of households in year Z (877,824) by the number in year Y (1,152,000), and then multiply by 100:

Rounding to the nearest whole percent, the result is 76%.

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QUESTION: 63

Which of the following categories accounted for an amount closest to 10 percent of the total per-pupil spending?

Administration
Food Services and Other
School Operation and Maintenance
Student Services
Transportation

Answer(s): C

Explanation:

The total per-pupil spending is $5,901. To find 10% of this amount:
10% of 5,901 = 5,901 × 0.10 = $590.1
Now, comparing this to the category expenditures:
Instruction: $3,590

School Operation and Maintenance: $612

Administration: $512

Student Services: $504

Food Services and Other: $438

Transportation: $245

The amount closest to $590.1 is $612 for School Operation and Maintenance.

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QUESTION: 64

If the total per-pupil spending for Transportation and Food Services and Other was 10 percent greater for the school year 1994-1995 than for the school year 1993-1994, approximately what was the total per-pupil spending for these two categories for the school year 1993-1994?

$620
$610
$600
$590
$580

Answer(s): A

Explanation:

For the school year 1994-1995, the total spending on Transportation and Food Services and Other is:
Transportation ($245) + Food Services and Other ($438) = $683 It is given that this spending was 10% greater than in 1993-1994. Let the 1993-1994 spending be X.
Since the 1994-1995 amount is 10% more than 1993-1994, we set up the equation:
X + 0.10X = 683
1.10X = 683
X = 683/1.10
X 621.82
Rounding to the nearest dollar, the total per-pupil spending for these two categories in 1993-1994 was approximately $620.

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