GRE Graduate Record Examination Test: Verbal, Quantitative, Analytical Writing GRE Test Exam Questions in PDF

Explanation:

From the pie chart, the sectors appear in this order (moving clockwise):
1. Instruction ($3,590)
2. Food Services and Other ($438)
3. Transportation ($245)
4. School Operation and Maintenance ($612)
5. Administration ($512)
6. Student Services ($504)
The correct order in decreasing size should be:
1. Instruction ($3,590)
2. School Operation and Maintenance ($612)
3. Administration ($512)
4. Student Services ($504)
5. Food Services and Other ($438)
6. Transportation ($245)
We now rearrange the sectors step by step by swapping adjacent sectors:
1. Swap Food Services and Other ($438) with School Operation and Maintenance ($612) New order:
Instruction, School Operation and Maintenance, Food Services and Other, Transportation, Administration,

Student Services
2. Swap Food Services and Other ($438) with Administration ($512) New order: Instruction, School Operation and Maintenance, Administration, Food Services and Other, Transportation, Student Services
3. Swap Food Services and Other ($438) with Student Services ($504) New order: Instruction, School Operation and Maintenance, Administration, Student Services, Food Services and Other, Transportation
4. Swap Transportation ($245) with Food Services and Other ($438) New order: Instruction, School Operation and Maintenance, Administration, Student Services, Transportation, Food Services and Other
5. Swap Transportation ($245) with Student Services ($504) New order: Instruction, School Operation and Maintenance, Administration, Transportation, Student Services, Food Services and Other
6. Swap Transportation ($245) with Administration ($512) New order: Instruction, School Operation and Maintenance, Transportation, Administration, Student Services, Food Services and Other
7. Swap Transportation ($245) with School Operation and Maintenance ($612) Final correct order:
Instruction, School Operation and Maintenance, Administration, Student Services, Food Services and Other, Transportation
The minimum number of adjacent interchanges required is seven.

Explanation:

The average annual decrease is calculated as:



Price in 1980 = $5,000 (slightly above $5,000 as observed)
Price in 1995 = $2,000
Years between 1980 and 1995 = 1995 - 1980 = 15 years
Total decrease = Price in 1980 - Price in 1995 = 5000 - 2000 = 3000

Explanation:

To determine which one-year time intervals saw a percent increase or decrease in net income greater than or equal to 50%, we can use the formula for percent change:



Calculate the percent changes for each interval:
1. 1995-1996:
Net income in 1995 = 1.0 million

Net income in 1996 = 1.5 million




2. 1996-1997:
Net income in 1996 = 1.5 million

Net income in 1997 = 1.0 million



3. 1997-1998:
Net income in 1997 = 1.0 million

Net income in 1998 = 2.0 million



4. 1998-1999:
Net income in 1998 = 2.0 million

Net income in 1999 = 1.1 million



5. 1999-2000:
Net income in 1999 = 1.1 million

Net income in 2000 = 0.5 million



Determine which intervals have a percent change greater than or equal to 50% 1995-1996: 50% increase

1996-1997: -33.33% decrease (not greater than or equal to 50%)

1997-1998: 100% increase (greater than 50%)

1998-1999: -45% decrease (not greater than or equal to 50%)

1999-2000: -54.55% decrease (greater than 50% decrease)

Explanation:

The problem refers to a normal distribution where the mean is 36.5. The probability P(36.5 < T < 43.9) = 0.475 means that the area between 36.5 and 43.9 under the normal distribution curve is 0.475.
This is approximately the area under the curve between the mean and a value 7.4 units away from the mean (since 43.9 - 36.5 = 7.4). Thus, we are looking for an estimate of the standard deviation such that the area from the mean to 43.9 corresponds to approximately 0.475 of the total area.
In a standard normal distribution, the area between the mean and one standard deviation is approximately 0.3413. Since we are looking for the area from the mean to 43.9 (which is 7.4 units away), this distance is likely a multiple of the standard deviation.
From the chart and common normal distribution tables, a distance of 7.4 units corresponds approximately to 2 standard deviations in a standard normal distribution.
Since the distance from the mean (36.5) to 43.9 is 7.4 units, and this distance represents approximately 2 standard deviations, we can estimate the standard deviation d as:

Explanation:

The given sequence is an arithmetic sequence, where the first term a1 = 5, and the common difference d = 2.
The formula for the n-th term of an arithmetic sequence is:
an = a1 + (n - 1) × d a83 = 5 + (83 - 1) × 2

a83 = 5 + (83 - 1) × 2
a83 = 5 + 164
a83 = 169
Thus, the 83rd term in the sequence is 169.

Explanation:

Explanation:

A fixed commission of $10 per bike, which for 5 bikes is:
10 × 5 = 50
An x percent commission on the total selling price of $6,500, which is:



Thus, the total commission equation is:



x = 2

Explanation:

1. The ratio of red balls to blue balls: 2:3
Let the number of red balls be 2x and the number of blue balls be 3x.
2. The ratio of blue balls to green balls: 4:3
Let the number of blue balls be 4y and the number of green balls be 3y.
Since both expressions represent the number of blue balls, we set them equal:
3x = 4y
Solving for x in terms of y:



Expressing all balls in terms of y:



· Red balls:
· Blue balls: 4y
· Green balls: 3y