Test Prep Graduate Management Admission Test: Analytical Writing Assessment (AWA), Quantitative section, Verbal section GMAT Test Exam Questions in PDF

Free Test Prep GMAT Test Dumps Questions (page: 14)

If x, y, and z are real numbers, which is always true?

I) x (yz) = (xy) z
II) x/y = y/z
III) z (x + y) = zx + zy

  1. I only
  2. II only
  3. I and II only
  4. I and III only
  5. I, II, and III

Answer(s): D

Explanation:

Statement I is an example of the associative property of multiplication and statement III is an example of the distributive property. These properties will hold for any real numbers that are substituted into them. Statement II is not a property of real numbers and may be true for certain numbers, but not for every real number.



If y = 6x, then 6y equals

  1. 6x
  2. 6x+1
  3. 6x + 6
  4. 6x
  5. 6x – 1

Answer(s): B

Explanation:

Since y = 6x, multiplying each side of the equation results in 6y = 6 (6x). Recall that since 6 = 61, 6x × 61 = 6x + 1 by the laws of exponents.



What is the smallest of six consecutive odd integers whose average (arithmetic mean) is x + 2?

  1. x – 5
  2. x – 3
  3. x – 1
  4. x
  5. x + 1

Answer(s): B

Explanation:

Remember that consecutive odd integers are numbers that are two apart in order, like 11, 13, and 15. The average of six consecutive odd integers will be an even number. If x + 2 is the average, then this value will be at the middle of the integers if they are arranged in order. Therefore, the three consecutive odd integers smaller than this are expressed as x + 1, x – 1, and x – 3 in descending order. The smallest odd integer is x – 3.



The product of a and b is equal to 11 more than twice the sum of a and b. If b = 7, what is the value of b – a?

  1. 2
  2. 5
  3. 7
  4. 24
  5. 35

Answer(s): A

Explanation:

Write an equation for the question by translating the first sentence. The product of a and b is ab, and 11 more than twice the sum of a and b translates to 2(a + b) + 11. The equation is ab = 2 (a + b) + 11. Substitute 7 for b.7a = 2 (a + 7) + 11. This simplifies to 7a = 2a + 14 + 11 by the distributive property and then becomes 7a = 2a + 25. Subtract 2a from both sides of the equation and then divide each side by 5; 7a – 2a = 2a – 2a + 25. . a = 5. The value of b – a = 7 – 5 = 2.



The instructions state that Cheryl needs 4/9 square yards of one type of material and 2/3 square yards of another type of material for a project. She buys exactly that amount. After finishing the project, however, she has 8/18 square yards left that she did not use. What is the total amount of square yards of material Cheryl used?

  1. 1/12
  2. 1/9
  3. 2/3
  4. 1 1/9
  5. 2 1/9

Answer(s): C

Explanation:

To solve the problem, you need to add 4/9 and 2/3 then subtract 8/18 since the amount she has not used is 8/18, which reduces to 4/9. If you were to add 4/9 and 2/3, and then subtract 4/9, you would end up with 2/3.



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