How long will it take for an initial deposit of $1,500 to grow to be $4,000, if the interest rate is 5% per year, compounded annually?
Answer(s): B
Either the $1,500 or the $4,000 must be entered as a negative number - it won't matter which. On the BAII Plus, press 5 I/Y, 1500 PV, 0 PMT, 4000 +/- FV, CPT N. On the HP12C, press 5 i, 2500 PV, 0 PMT, 4000 CHS FV,F. Note that the HP12C will indicate 21 years for the answer. Make sure the BAII Plus has the P/Y value set to 1.
Ball-Bearing, Inc. produces ball bearings automatically on a Kronar BBX machine. For one of the ball bearings, the mean diameter is set at 20mm. the standard deviation of the production over a long period of time was computer to be 0.150 mm. What percent of the ball bearings will have a diameter of 20.27 mm or more?
Answer(s): E
z = (x-u)/sigma = 20.27 - 20/0.15 = 1.8. from the z-table, z = 1.8 is 0.4641. So 1.0 - 0.9641 = 0.0359.
In an investment environment, an initial outlay of $100 grows to $156 in 7 years. The quarterly compounded rate of annual interest implicit in this is:
There are 28 quarters in 7 years. If the quarterly compounded rate is r, then we have 100*(1+r/4)^28 = 156, giving r = 6.4%
David's gasoline station offers 4 cents off per gallon if the customer pays in cash and does not use a credit card. Past evidence indicates that 40% of all customers pay in cash. During a one-hour period twenty-five customers buy gasoline at this station. What is the probability that at least ten pay in cash?
This is a binomial distribution: n!(p^r)(q^(n-r))/r!(n-r)!. n = 25, r = 10, p = 0.4 q = 0.6 P(10) = 25!(0.4^10)(0.6^15)/10!15! = 0.1612P(11) = 25!(0.4^11)(0.6^14)/11!14! = 0.1465P(12) = 25!(0.4^12)(0.6^13)/12!13! = 0.1140P(13) = 25!(0.4^13)(0.6^12)/13!12! = 0.0760P(14) = 25!(0.4^14)(0.6^11)/14!11! = 0.0434P(15) = 25!(0.4^15)(0.6^10)/15!10! = 0.0212P(16) = 25!(0.4^16)(0.6^9)/16!9! = 0.0088P(17) = 25!(0.4^17)(0.6^8)/17!8! = 0.0031Summing up we get close to 0.574.We can continue until r = 25 but the probability gets smaller and converges to 0.575.
Consider the following three investments:Future valueyearsinterest rate1.$50,000 89% per year2.$20,000 612% per year3.$35,000 37% per yearThe present values of the 3 investments are:
Answer(s): C
Future value = Present value*(1+r)^N for annual compounding. Therefore, Future valueyearsratePresent Value1.50,000 89% 50,000/(1.09)^8 = 25,0932.20,000 612% 20,000/(1.12)^6 = 10,1333.35,000 37% 35,000/(1.07)^3 = 28,570Note that the future value must always be greater than the present value.
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question #18s answer should be a, not d. this should be corrected. it should be minvalidityperiod
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q:37 c is correct
q6 exam topic: terramearth, c: correct answer: copy 1petabyte to encrypted usb device ???
explained answers
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question 128 the answer should be static not auto
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q31 answer should be d i think
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admin guide (windows) respond to malicious causality chains. when the cortex xdr agent identifies a remote network connection that attempts to perform malicious activity—such as encrypting endpoint files—the agent can automatically block the ip address to close all existing communication and block new connections from this ip address to the endpoint. when cortex xdrblocks an ip address per endpoint, that address remains blocked throughout all agent profiles and policies, including any host-firewall policy rules. you can view the list of all blocked ip addresses per endpoint from the action center, as well as unblock them to re-enable communication as appropriate. this module is supported with cortex xdr agent 7.3.0 and later. select the action mode to take when the cortex xdr agent detects remote malicious causality chains: enabled (default)—terminate connection and block ip address of the remote connection. disabled—do not block remote ip addresses. to allow specific and known s
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question 5, it seems a instead of d, because: - care plan = case - patient = person account - product = product2;