The following is a distribution of monthly commissions:Monthly Commissions Class Frequencies$600 - $7993$800 - $9997$1,000 - $1,19911$1,200 - $1,39922$1,400 - $1,59940$1,600 - $1,79924$1,800 - $1,9999$2,000 - $2,1994Referring to the table above, what is the relative frequency of those salespersons that earn more than $1,599?
Answer(s): E
This is found by adding up all the frequencies of the classes above $1599. In this case 24 + 9 + 4 = 37. Then we divide this by the total frequencies, which is 120. Therefore, 37/120 = 30.8%
The probability of the occurrence of an airplane crash and a successful resolution to a labor strike is called:
Answer(s): C
A joint probability takes the form of P(AB), the probability that an event A (an airplane crash) and an event B (the resolution of a strike) both happen.
How much interest would an original $500 deposit earn at 5% per year simple interest after 14 months?
Answer(s): A
The question only asks for the interest, not the ending balance. On the BAII Plus, press 500 x 0.05 x 14 divide 12 = to see the answer. On the HP12C, press 500 ENTER 0.05 x 14 x 12 divide to see the answer.
In the regression equation, what does the letter "a" represent?
Answer(s): B
The regression is written as Y' = a + bX. The letter "a" is the Y intercept and b is the slope of the line.
Suppose you have two assets, A and B. Over the past 3 periods, A has returned 8%, 2%, and 6%, while B has returned 11%, -5%, and 20%. What is the return covariance between assets A and B?
First we must find the expected returns for A and B. These are 5.33% and 8.67%. Second, we find the difference between each observation and the average: (8% - 5.33%), (2% - 5.33%), and (6% - 5.33%) for A, and (11% - 8.67%), (-5% - 8.67%), and (20% - 8.67%) for B. Next, we multiply these together and sum them:(8% - 5.33%)*(11% - 8.67%) + (2% - 5.33%)*(-5% - 8.67%) + (6% - 5.33%)*(20% - 8.67%). The sum of these is 59.33%. The covariance is the probability weighted average of these cross products, so we divide by 3 to get 19.78%%. Note, we could have divided each cross product by 3 rather than the sum of the cross products. If the observations did not have the same probability or frequency, we would need to treat each cross product separately rather than divide at the end.
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