ASVAB Test Exam dumps PDF | Exam-Dumps.net (Page: 14)

QUESTION: 66

The price of daily admission at an amusement park is $36. The park sells an unlimited season pass for $240.
How many trips would you need to make with the season ticket in order for it to cost less than paying the daily admission rate?

6
7
8
9

Answer(s): B

Explanation:

Let x equal the number of daily tickets you would purchase. 36x = the daily ticket cost.
240 < 36x
240/36 < x
62/3 < x
You would need to use the ticket more than 62/3 times (or 7 times) in order for it to be cheaper to use the season ticket.

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QUESTION: 67

A plumber needs four lengths of pipe, each 3-feet, 6-inches long. Pipes are sold by the foot. How many feet does he need to buy?

15
16
14
12

Answer(s): C

Explanation:

Convert the pipe length to inches: 3 feet, 6 inches = 42 inches. Multiply 42 inches by the number of pipes needed to find the number of inches of pipe needed: 42 × 4 = 168. Divide the total amount of pipe needed in inches by 12 to determine how many feet of pipes are needed: 168 ÷ 12 = 14.

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QUESTION: 68

The product of two consecutive odd numbers is 399.
What are the numbers?

17 and 19
19 and 21
21 and 23
25 and 27

Answer(s): B

Explanation:

The fastest way to solve this would be to simply multiply the possible choices together (19 × 21 = 399). You can also solve this with algebra.

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QUESTION: 69

A personal trainer earns a 65% commission on her training sales.
If she sells $530.00 worth of training, how much commission does she make?

$874.50
$34.45
$344.50
$185.50

Answer(s): C

Explanation:

Multiply her total sales by her percent commission to find her commission: $530.00 × 0.65 = $344.50.

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QUESTION: 70

A rectangle is one inch longer than it is wide. Its diameter is five inches.
What's the width of the rectangle?

2 inches
3 inches
4 inches
5 inches

Answer(s): B

Explanation:

The diagonal formula for a rectangle is D2 = L2 + W2. In this case, D = 5, and L = W + 1.
Substituting the known values into the formula results in 52 = (W + 1)2 + W2.
25 = (W + 1)(W + 1) + W2
25 = W2 + 2W + 1 + W2
25 = 2W2 + 2W + 1
(Note: This equation is a quadratic equation and can be solved by setting it equal to zero and factoring.) 0 = 2W2 + 2W 24
1/2(0) = 1/2(2 W2 + 2W 24)
0 = W2 + W 12
0 = (W 3)(W + 4)
W 3 = 0W + 4 = 0
W = 3
W = 4 (not a possible solution)

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