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Huawei HCIA-Datacom V2.0 H12-811_V2.0 Dumps in PDF

Free Huawei H12-811_V2.0 Real Questions (page: 8)

Page 2 of 9 H12-811_V2.0 PDF — 106 Questions

QUESTION: 9

On the network shown in the figure, the administrator creates Eth-Trunk 1 in manual mode on SW1 and SW2, and adds GE1/0/1 and GE1/0/2 on both switches to the Eth-Trunk. After the administrator runs the display interface brief command on SW1, the administrator finds that GE1/0/1 is Up and GE1/0/2 is Down.
Which of the following statements is true about this scenario?

Eth-Trunk 1 is Up because it is Up as long as one member interface is Up.
Eth-Trunk 1 is Down because the states of member interfaces must be the same in manual mode.
Eth-Trunk 1 is Down because it has only two member interfaces and the minimum number of active links is not reached after one member interface is Down.
Eth-Trunk 1 is Down because all member interfaces of the Eth-Trunk must be Up.

Answer(s): A

Explanation:

For an Eth-Trunk operating in manual load-balancing mode, the logical Eth-Trunk interface can remain Up as long as at least one member link is operational and properly added to the trunk. Therefore, if GE1/0/1 is Up and GE1/0/2 is Down, Eth-Trunk 1 can still stay Up, making option A correct.
Option B is incorrect because member interfaces in a manual Eth-Trunk do not need to be in identical physical states for the trunk itself to remain operational. Option C is also incorrect because there is no inherent rule here that two-member trunks must have both links active unless a separate minimum-links mechanism has been explicitly configured. No such condition is stated in the question. Option D is false because one of the key purposes of Eth-Trunk is redundancy; requiring all member interfaces to be Up would defeat that design advantage. HCIA-Datacom teaches that Eth-Trunk enhances link reliability by allowing continued forwarding when part of the bundle fails, provided the trunk still has an active forwarding member.

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QUESTION: 10

The administrator configures an Eth-Trunk in LACP mode between two switches, and sets the maximum number of active links in the Eth-Trunk to 3 and the number of remaining standby links to 1. If one of the active links fails, the two switches automatically adjust the number of active links to 2 through negotiation, and the standby link remains in the standby state.

TRUE
FALSE

Answer(s): B

Explanation:

This statement is false. In an Eth-Trunk operating in LACP mode, if the administrator sets the maximum number of active links to 3 and there is 1 standby link, then when one active member fails, LACP can automatically promote the standby member to active status. The purpose of the standby member is to maintain the configured active-link capacity whenever possible.
Therefore, after one active link fails, the normal expectation is not that the active-link count is reduced from 3 to 2 while the standby link remains idle. Instead, the standby link should participate and replace the failed member, so that the Eth-Trunk continues operating with 3 active links if the standby link and negotiation conditions are normal. This reflects the redundancy and fast recovery capabilities of LACP-based aggregation. HCIA-Datacom highlights that compared with manual mode, LACP provides more intelligent link selection, active/standby management, and fault adaptation. The statement is wrong because it ignores the intended behavior of the standby link in maintaining the number of active forwarding links after a failure.

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QUESTION: 11

In the figure, both PC1 and PC2 belong to VLAN 10. Interface GE1/0/1 on SW1 is a trunk interface with the default PVID, and interface GE1/0/2 on SW1 is an access interface in VLAN 10.
Which of the following statements are true about the forwarding of data frames between PC1 and PC2? (Select all that apply)

After receiving the data frame sent from PC1 to PC2, SW1 adds the VLAN 10 tag to the data frame and then accepts the data frame.
SW1 accepts the data frame sent from PC1 to PC2, but discards the data frame returned from PC2 to PC1.
The data frame processed inside SW1 does not carry any VLAN tag.
SW1 removes the VLAN 10 tag from the data frame before forwarding it from GE1/0/2 to PC2.

Answer(s): A,D

Explanation:

When a switch receives an untagged frame from a user host on an access interface, it associates that frame with the VLAN configured on the interface. In this scenario, PC1 and PC2 are in VLAN 10, and GE1/0/2 is an access interface in VLAN 10. After SW1 receives the frame from PC1, it internally associates the frame with VLAN 10, so option A is correct in the practical VLAN-processing sense used in HCIA-Datacom questions.
When the frame is forwarded out an access interface toward PC2, the switch sends it without a VLAN tag, because end hosts normally do not process 802.1Q tags. Therefore, option D is correct. Option B is incorrect because both hosts are in the same VLAN and can communicate normally; SW1 does not discard the return traffic for that reason. Option C is not correct in the standard VLAN switching model used by Huawei training, because the switch performs forwarding based on VLAN membership and internally processes the frame as belonging to VLAN 10. This question mainly checks understanding of access/trunk behavior and tag handling on ingress and egress.

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QUESTION: 12

In the STP topology shown in the figure, all links have the same path cost, and SW1 is the root bridge.
Which of the following ports will become designated ports? (Select all that apply)

GE1/0/2 of SW2
GE1/0/1 of SW2
GE1/0/3 of SW3
GE1/0/1 of SW4

Answer(s): A,B,C

Explanation:

In STP, the root bridge has all its active ports elected as designated ports on each connected segment. On non-root switches, one port is selected as the root port, and on each LAN segment, one designated port is elected based on the best BPDU. Since SW1 is the root bridge and all links have equal cost, the election depends first on the path cost to the root, then on bridge ID, and then on port ID if needed.
According to the topology, the ports that become designated are GE1/0/2 of SW2, GE1/0/1 of SW2, and GE1/0/3 of SW3, which correspond to option A, B, and
C. Option D is not a designated port in this topology because that segment has another port with a superior BPDU and therefore SW4’s port does not win the designated-port election. HCIA-Datacom emphasizes that designated ports are elected per segment, not per switch, and that every non-root switch must compare received BPDUs to determine root and designated roles. This question tests the ability to apply STP election logic rather than simply memorizing port-role definitions.

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QUESTION: 13

On the network shown in the figure, all switches run STP. All links have a path cost of 20, and SW1 is the root bridge.
What is the root path cost (RPC) of SW4?

20
40
60
80

Answer(s): B

Explanation:

The root path cost (RPC) of a switch is the total path cost from that switch to the root bridge along the selected spanning-tree path. Since SW1 is given as the root bridge, its RPC is 0. Each link in the topology has a path cost of 20. To determine SW4’s RPC, you identify the shortest active STP path from SW4 to SW1.
Based on the topology used in the question, SW4 reaches SW1 through a path containing two links. Therefore, the total root path cost is 20 + 20 = 40, which makes option B correct. This is a standard STP calculation. HCIA-Datacom uses RPC as one of the main comparison parameters in root-port election on non-root switches. A lower RPC means a better path toward the root bridge. If multiple candidate ports have the same RPC, the switch then compares the sender’s bridge ID and port I
D. This question checks whether the learner understands that RPC is cumulative across the spanning-tree forwarding path and is not simply the cost of a single directly connected link unless the switch is directly attached to the root bridge.

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QUESTION: 14

On a switched network where STP is enabled on all devices, when a downstream device detects a topology change, it continuously sends configuration BPDUs to the upstream device until the root bridge is informed of the topology change.

TRUE
FALSE

Answer(s): B

Explanation:

This statement is false. In classic STP, when a non-root switch detects a topology change, it does not continuously send configuration BPDUs upstream to notify the root bridge. Instead, it sends a Topology Change Notification (TCN) BPDU toward the root bridge through its root port. Each upstream switch acknowledges the TCN and forwards it further until it reaches the root bridge.
After the root bridge receives the topology change notification, the root bridge sets the Topology Change (TC) flag in its configuration BPDUs, and those configuration BPDUs are then propagated throughout the network. Therefore, topology-change notification and normal configuration BPDU transmission are different functions. The statement is wrong because it confuses TCN BPDUs with configuration BPDUs, and also inaccurately describes the notification behavior. HCIA-Datacom requires learners to distinguish between these BPDU types and understand how STP reacts to topology changes by accelerating MAC address aging and informing the network through the root bridge. This process helps the Layer 2 topology converge and reduces long-lasting forwarding inconsistencies after a link or port-state change.

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QUESTION: 15

After the root bridge is elected on an STP network, which of the following parameters may be compared by ports on non-root bridge nodes to elect the root port? (Select all that apply)

PID of a port on the local device
Root path cost (RPC)
BID of the device that sends BPDUs
PID of a port on the device that sends BPDUs

Answer(s): A,B,C,D

Explanation:

On a non-root bridge, the root port is the port that receives the best BPDU toward the root bridge. STP selects the root port by comparing several parameters in order. The first important parameter is the root path cost (RPC), so option B is correct. If multiple ports have the same RPC, the switch then compares the bridge ID (BID) of the upstream device sending the BPDU, making option C correct. If those are still equal, the switch compares the port ID (PID) of the upstream sending port, so option D is also correct.
If all of those values remain identical from the switch’s perspective, the device can finally compare the local port ID to determine which local interface becomes the root port, so option A is also correct. HCIA-Datacom teaches this comparison logic as part of STP election rules. The process ensures deterministic selection of a single root port on every non-root switch. Understanding the comparison sequence is essential for predicting STP topology behavior and for influencing port roles through path cost tuning or bridge-priority adjustments during campus network design and troubleshooting.

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QUESTION: 16

On an STP network, an administrator wants SW2 to be elected as the root bridge.
Which of the following methods can be used to achieve this goal?

Set a lower port priority on SW2.
Set a higher system priority on SW2.
Set a lower system priority on SW2.
Set a lower root path cost on SW2.

Answer(s): C

Explanation:

In STP, the root bridge is elected based on the lowest bridge ID (BID). A BID is composed of the bridge priority and the MAC address of the switch. The device with the smallest BID becomes the root bridge. Therefore, if an administrator wants SW2 to become the root bridge, the most direct and correct method is to configure a lower system priority on SW2, making option C correct.
Option A is incorrect because port priority affects port-role selection in some tie-breaking scenarios, but it does not determine root-bridge election. Option B is the opposite of what is required, because a higher system priority makes the BID larger and reduces the chance of being elected as root. Option D is also incorrect because root path cost is used by non-root bridges to select the best path to the existing root bridge; it does not determine which switch becomes the root bridge in the first place. HCIA-Datacom stresses that bridge priority tuning is the standard administrative method used to control root bridge placement in campus networks for stable and predictable Layer 2 topology design.

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Community Helper

4/25/2026 2:03:10 AM

Q23: Fabric Admin is correct. Because Domain admin cannot create domains. Only Fabric Admin can among the given options. Q51: Wrapping @pipeline.parameter.param1 inside {} will return a string. But question requires the expression to return Int, so correct answer should be @pipeline.parameter.param1 (no {})

A

AI Tutor Explanation

4/23/2026 3:07:03 PM

Question 62:

Correct answer: D (per the page)

Note: The explanation text on the page describes option B (use ZDX score and Analyze Score to trigger the Y Engine analysis), indicating a mismatch between the stated answer and the rationale.

Key concept: For fast root-cause analysis, leverage telemetry and auto-correlated insights:

- Use the user’s ZDX score for AWS and run Analyze Score to activate the Y Engine, which correlates metrics across network, client, and application to pinpoint the issue quickly.

Why the other options are less effective:

- A: Only checks for outages; doesn’t provide actionable root-cause analysis. - C: Deep Trace helps visibility but is manual and time-consuming. - D: Packet capture is invasive and slow; not the quickest path to root cause.

A

AI Tutor Explanation

4/23/2026 12:26:21 PM

Question 32:

Answer: A (2.4GHz)

Why: Lower-frequency signals have longer wavelengths and experience less attenuation when passing through walls and obstacles. Higher frequencies (5GHz, 6GHz) are more easily blocked by walls. NFC operates over very short distances and is not meant to penetrate walls. So 2.4 GHz best penetrates physical objects like walls.

A

AI Tutor Explanation

4/21/2026 8:48:36 AM

Question 3:

False is the correct answer (Option B).

Why:

In Snowflake, a database is a metadata object that exists within a single Snowflake account. Accounts are isolated—there isn’t one database that lives in multiple accounts.
You can access data across accounts via data sharing or database replication, but these create separate database objects in the other accounts (e.g., a database in the consumer account created from a share), not a single shared database across accounts.

So a single database cannot exist in more than one Snowflake account.

A

Anonymous User

4/16/2026 10:54:18 AM

Question 1:

Correct answer: E — date = sys.argv[1]
Why this is correct:

- When a Databricks Job passes parameters to a notebook, those parameters are supplied to the notebook's Python process as command-line arguments. The first argument after the script name is sys.argv[1], so date = sys.argv[1] captures the passed date value directly.

How it compares to other options:

- date = spark.conf.get("date") reads from Spark config, not from job parameters. - input() waits for user input at runtime, which isn’t how job parameters are provided. - date = dbutils.notebooks.getParam("date") would work if the notebook were invoked via dbutils.notebook.run with parameters, not

A

Anonymous User

4/15/2026 4:42:07 AM

Question 528:

Correct answer: NSG flow logs for NSG1 (Option B)

Why:

- Traffic Analytics uses NSG flow logs to analyze traffic patterns. You must have NSG flow logs enabled for the NSGs you want to monitor. - An Azure Log Analytics workspace is also required to store and query the traffic data. - Network Watcher must be available in the subscription for traffic analytics to function.

What to configure (brief steps):

- Ensure Network Watcher is enabled in the East US region (for the subscription/region). - Enable NSG flow logs on NSG1. - Ensure a Log Analytics workspace exists and is accessible (read/write) so Traffic Analytics can store and query logs.

Why other options aren’t correct:

- “Diagnostic settings for VM1” or “Diagnostic settings for NSG1” alone don’t guarantee flow logs are captured and sent to Log Analytics, which Traffic Analytics relies on. - “Insights for VM1” is not how Traffic Analytics collects traffic data.

A

Anonymous User

4/15/2026 2:43:53 AM

Question 23:
The correct answer is Domain admin (option B), not Fabric admin.

Domain admin provides domain-level management: create domains/subdomains and assign workspaces within those domains, which matches the tasks while following least privilege.
Fabric admin is global-level access and is more privileges than needed for this scenario (it would grant broader control across the Fabric environment).

A

Anonymous User

4/14/2026 12:31:34 PM

Question 2:
For question 2, the key concept is the Longest Prefix Match. Routers pick the route whose subnet mask is the most specific (largest prefix length) that still matches the destination IP.
From the options:

A) 10.10.10.0/28 ? 10.10.10.0–10.10.10.15
B) 10.10.13.0/25 ? 10.10.13.0–10.10.13.127
C) 10.10.13.144/28 ? 10.10.13.144–10.10.13.159
D) 10.10.13.208/29 ? 10.10.13.208–10.10.13.215

The destination Host A’s IP must fall within 10.10.13.208–10.10.13.215 for the /29 to be the best match. Since /29 is the longest prefix among the matching options, Router1 will use 10.10.13.208/29.
Thus, the correct answer is D.

S

srameh

4/14/2026 10:09:29 AM

Question 3:

Correct answer: Phase 4, Post Accreditation

Explanation:

- In DITSCAP, the four phases are: - Phase 1: Definition (concept and requirements) - Phase 2: Verification (design and testing) - Phase 3: Validation (fielding and evaluation) - Phase 4: Post Accreditation (ongoing operations and lifecycle management) - The description—continuing operation of an accredited IT system and addressing changing threats throughout its life cycle—fits the Post Accreditation phase, which covers operations, maintenance, monitoring, and reauthorization as threats and environment evolve.

O

onibokun10

4/13/2026 7:50:14 PM

Question 129:
Correct answer: CNAME

A CNAME record creates an alias for a domain, so newapplication.comptia.org will resolve to whatever IP address www.comptia.org resolves to. This ensures both names point to the same resource without duplicating the IP.
Why not the others:

- SOA defines authoritative information for a zone. - MX specifies mail exchange servers. - NS designates name servers for a zone.

Notes: The alias name (newapplication.comptia.org) should not have other records if you use a CNAME for it, and CNAMEs aren’t used for the zone apex (root) domain. This scenario uses a subdomain, so a CNAME is appropriate.

A

Anonymous User

4/13/2026 6:29:58 PM

Question 1:

Correct answer: C

Why this is best:

- Uses OS Login with IAM, so SSH access is granted via Google accounts rather than distributing per-user SSH keys. - Granting the compute.osAdminLogin role to a Google group gives admin access to all team members in a centralized, auditable way. - Access is auditable: Cloud Audit Logs show who accessed which VM, satisfying the security requirement to determine who accessed a given instance.

How it works:

- Enable OS Login on the project/instances (enable-oslogin metadata). - Add the team’s

A

Anonymous User

4/13/2026 1:00:51 PM

Question 2:

Answer: D. Azure Advisor

Why: To view security-related recommendations for resources in the Compute and Apps area (including App Service Web Apps and Functions), you use Azure Advisor. Advisor surfaces personalized best-practice recommendations across resources, including security, and shows which resources are affected and the severity.

Why not the others:

- Azure Log Analytics is for ad-hoc querying of telemetry, not for viewing security recommendations. - Azure Event Hubs is for streaming telemetry data, not for security recommendations.

Quick tip: In the portal, navigate to Azure Advisor and check the Security recommendations for App Services to see actionable items and affe

Brazil

D

Don

4/11/2026 5:36:42 AM

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M

Mogae Malapela

4/8/2026 6:37:56 AM

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A

Anon

4/6/2026 5:22:54 PM

Are these the same questions you have to pay for in ExamTopics?

L

LRK

3/22/2026 2:38:08 PM

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R

Rian

3/19/2026 9:12:10 AM

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G

Gerrard

3/18/2026 6:58:37 AM

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V

Vineet Kumar

3/6/2026 5:26:16 AM

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1/20/2026 8:25:24 AM

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N

NJ

12/24/2025 10:39:07 AM

Helpful to test your preparedness before giving exam

A

Ashwini

12/17/2025 8:24:45 AM

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J

Jagadesh

12/16/2025 9:57:10 AM

Good explanation

S

shobha

11/29/2025 2:19:59 AM

very helpful

P

Pandithurai

11/12/2025 12:16:21 PM

Question 1, Ans is - Developer,Standard,Professional Direct and Premier

E

Einstein

11/8/2025 4:13:37 AM

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D

David

10/31/2025 4:06:16 PM

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Thor

10/21/2025 5:16:29 AM

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Vladimir

9/25/2025 9:11:14 AM

173 question is A not D

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khaos

9/21/2025 7:07:26 AM

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9/15/2025 11:21:52 PM

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E

Einstein

9/2/2025 7:42:00 PM

Passed this exam today. All questions are valid and this is not something you can find in ChatGPT.

V

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8/22/2025 4:16:51 AM

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M

Matt

7/31/2025 11:44:40 PM

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