HPE6-A85 Exam Questions and Answers

QUESTION: 11

Based on the "snow ip route" output on an AruDaCX 8400. what type of route is "10.1 20 0/24, vrf default via 10.1.12.2. [1/0]"?

local
static
OSPF
connected

Answer(s): B

Explanation:

A static route is a route that is manually configured on a router or switch and does not change unless it is modified by an administrator. Static routes are used to specify how traffic should reach specific destinations that are not directly connected to the device or that are not reachable by dynamic routing protocols. In Aruba CX switches, static routes can be configured using the ip route command in global configuration mode. Based on the "show ip route" output on an Aruba CX 8400 switch, the route "10.1 20 0/24, vrf default via 10.1.12.2, [1/0]" is a static route because it has an administrative distance of 1 and a metric of 0, which are typical values for static routes.

Reference:

https://en.wikipedia.org/wiki/Static_routing https://www.arubanetworks.com/techdocs/AOS- CX_10_04/NOSCG/Content/cx-noscg/ip-routing/static-routes.htm https://www.arubanetworks.com/techdocs/AOS-CX_10_04/NOSCG/Content/cx-noscg/ip- routing/show-ip-route.htm

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QUESTION: 12

Which device configuration group types can a user define in Aruba Central during group creation? (Select two.)

Security group
Template group
Default group
Ul group
ESP group

Answer(s): B,C

Explanation:

In Aruba Central, during the creation of a device configuration group, users can define various types of groups to manage and apply configurations to devices centrally. Among the options, "Template group" and "Default group" are valid types. A "Template group" allows the definition of configuration settings in a template format, which can be applied to multiple devices or device groups, ensuring consistency and efficiency in configurations across the network. A "Default group" is typically a predefined group in Aruba Central that applies a basic or initial set of configurations to devices that are not assigned to any other specific group. This helps in initial provisioning and management of devices. The other options, such as "Security group," "UI group," and "ESP group," are not standard group types defined in Aruba Central for device configuration purposes.

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QUESTION: 13

What is the correct command to add a static route to a class-c-network 10.2.10.0 via a gateway of 172.16.1.1?

ip-route 10.2.10.0/24 172.16.1.1
ip route 10.2.10.0.255.255.255.0 172.16.1.1 description aruba
ip route 10.2.10.0/24.172.16.11
ip route-static 10.2 10.0.255.255.255.0 172.16.1.1

Answer(s): A

Explanation:

The correct command to add a static route to a class-c-network 10.2.10.0 via a gateway of 172.16.1.1 is ip-route 10.2.10.0/24 172.16.1.1 . This command specifies the destination network address (10.2.10.0) and prefix length (/24) and the next-hop address (172.16.1 .1) for reaching that network from the switch. The other commands are either incorrect syntax or incorrect parameters for adding a static route.

Reference:

https://www.arubanetworks.com/techdocs/AOS-CX_10_04/NOSCG/Content/cx-noscg/ip-routing/static-routes.htm To add a static route in network devices, including Aruba switches, the correct command format generally includes the destination network, subnet mask (or CIDR notation for the mask), and the next-hop IP address. The command "ip route 10.2.10.0/24 172.16.1.1" correctly specifies the destination network "10.2.10.0" with a class C subnet mask indicated by "/24", and "172.16.1.1" as the next-hop IP address. This command is succinct and follows the standard syntax for adding a static route in many network operating systems, including ArubaOS-CX. The other options either have incorrect syntax or include additional unnecessary parameters that are not typically part of the standard command to add a static route.

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QUESTION: 14

You need to configure wireless access for several classes of loT devices, some of which operate only with 802 11b. Each class must have a unique PSK and will require a different security policy applied as a role There will be 15-20 different classes of devices and performance should be optimized Which option fulfills these requirements''

Single SSID with MPSK for each loT class using 5 GHz and 6 GHz bands
Single SSID with MPSK for each loT class using 2.4GHz and 5 GHz bands
Individual SSIDs with unique PSK for each loT class, using 5GHz and 6 GHz bands
Individual SSIDs with unique PSK for each loT class, using 2.4GHZ and 5GHz band

Answer(s): B

Explanation:

For configuring wireless access for multiple classes of IoT devices with varying security requirements, using a single SSID with Multiple Pre-Shared Keys (MPSK) is an efficient solution. MPSK allows different devices or groups of devices to connect to the same SSID but with unique PSKs, facilitating unique security policies for each class. Given that some IoT devices only support 802.11b, which operates in the 2.4GHz band, it is essential to include the 2.4GHz band in the configuration. The 5GHz band should also be included to support devices capable of operating in that band and to optimize network performance. The 6GHz band (option A) is not suitable since 802.11b devices are not compatible with it. Individual SSIDs for each IoT class (options C and D) would unnecessarily complicate network management and SSID overhead.

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QUESTION: 15

The noise floor measures 000000001 milliwatts, and the receiver's signal strength is -65dBm.
What is the Signal to Noise Ratio?

35 dBm
15 dBm
45 dBm
25 dBm

Answer(s): D

Explanation:

The signal to noise ratio (SNR) is a measure that compares the level of a desired signal to the level of background noise. SNR is defined as the ratio of signal power to the noise power, often expressed in decibels (dB). A high SNR means that the signal is clear and easy to detect or interpret, while a low SNR means that the signal is corrupted or obscured by noise and may be difficult to distinguish or recover. To calculate the SNR in dB, we can use the following formula:
SNR (dB) = Signal power (dBm) - Noise power (dBm)
In this question, we are given that the noise floor measures -90 dBm (0.000000001 milliwatts) and the receiver's signal strength is -65 dBm (0.000316 milliwatts). Therefore, we can plug these values into the formula and get:
SNR (dB) = -65 dBm - (-90 dBm) SNR (dB) = -65 dBm + 90 dBm SNR (dB) = 25 dBm Therefore, the correct answer is that the SNR is 25 dBm.

Reference:

3 https://en.wikipedia.org/wiki/Signal-to-noise_ratio

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HP HPE6-A85 Exam (page: 3) HP Aruba Certified Campus Access Associate Updated on: 12-Feb-2026

QUESTION: 11

Explanation:

Reference:

QUESTION: 12

Explanation:

QUESTION: 13

Explanation:

Reference:

QUESTION: 14

Explanation:

QUESTION: 15

Explanation:

Reference:

HP HPE6-A85 Exam (page: 3)
HP Aruba Certified Campus Access Associate
Updated on: 12-Feb-2026