A survey of 500 households found that 450 households had a microwave oven, 300 had a food processor, and 150 had a trash compactor. Each of the 500 households had at least one of the appliances, and more than 100 households had all three appliances. Which of the following could be the number of households that had a food processor and a trash compactor but no microwave oven? (Choose all that apply.)
Answer(s): A,B,C,D,E
Let:M be the number of households with a microwave.F be the number of households with a food processor.T be the number of households with a trash compactor.x be the number of households that have all three appliances. We know that x > 100.Total households = |M| + |F| + |T| - (Households with exactly two appliances) - 2x.500 = 450 + 300 + 150 - (Households with exactly two appliances) - 2x.500 = 900 - (Households with exactly two appliances) - 2x.Households with exactly two appliances + 2x = 400.The households with exactly two appliances consist of:Households with a microwave and a food processor only.Households with a microwave and a trash compactor only.Households with a food processor and a trash compactor only, which we denote as y.Since we know that the total of all these must be 400 - 2x, we solve:y 400 - 2(100), since x > 100.y 200.Now we check the answer choices: 5, 35, 50, 65, and 100. Since all these values are less than or equal to 200, they are all valid possibilities.
FILL BLANKA square plot of land has the same perimeter as a rectangular plot of land that measures 25 meters by 35 meters. If both plots of land are level, what is the area of the square plot of land? (Enter your answer as an integer or a decimal in the answer box. Backspace to erase.)
Answer(s): A
The perimeter P of a rectangle is given by the formula:P = 2 × (length + width)For the rectangular plot, the length is 25 meters and the width is 35 meters. So, the perimeter of the rectangular plot is:P = 2 × (25 + 35) = 2 × 60 = 120 metersThe perimeter of the square is the same as the perimeter of the rectangular plot, which is 120 meters. The perimeter of a square is given by:P = 4 × side lengthLet the side length of the square be s. Since the perimeter is 120 meters, we have:4 × s = 120The area A of a square is given by:A = s2A = 302 = 900 square meters
FILL BLANKAn apple falls straight to the ground from a tree branch 8 meters above the ground. The apple's height above the ground, t seconds after it starts falling, is H meters, where H = 8 - 4.9t2 and t 0. How many seconds after the apple starts falling does it hit the ground?Give your answer to the nearest 0.1 second. (Enter your answer as an integer or a decimal in the answer box.Backspace to erase.)
H = 8 - 4.9t2, where t is the number of seconds after the apple starts falling.The apple hits the ground when H = 0, so we set up the equation:8 - 4.9t2 = 04.9t2 = 8t 1.28Rounding 1.28 to the nearest 0.1, we get 1.3 seconds.
FILL BLANKA lecture hall has 15 rows of seats. There are n - 2 seats in the first row and n seats in each of the other rows. If there are no other seats in the lecture hall and the total number of seats in the lecture hall is between 180 and 200, what is the total number of seats in the lecture hall? (Enter your answer as an integer or a decimal in the answer box. Backspace to erase.)
The lecture hall has 15 rows of seats.The first row has n - 2 seats.Each of the other 14 rows has n seats.The total number of seats, T, can be calculated as:T = (n - 2) + 14nT = (n - 2) + 14n = 15n - 2We are told that the total number of seats, T, is between 180 and 200:180 < 15n - 2 < 200182 < 15n < 20212.13 < n < 13.47Since n must be an integer, the only possible value for n is 13.Substitute n = 13 into the equation for the total number of seats:T = 15(13) - 2 = 195 - 2 = 193
FILL BLANKThe integer n is greater than 1, and set S = {5 - n, 5 - n2, 5 + n). If the difference between the greatest number in S and the least number in S is 72, what is the value of n? (Enter your answer as an integer or a decimal in the answer box. Backspace to erase.)
To determine the greatest and least numbers in the set, we need to compare the three values:5 - n5 - n25 + nWe know that the greatest number will have the highest value, and the least number will have the lowest value.Since n is greater than 1, we will try different values of n to find the one that satisfies the condition that the difference between the greatest and least numbers is 72.Try n = 9:The three numbers in the set are:5 - n = 5 - 9 = -45 - n2 = 5 - 92 = 5 - 81 = -765 + n = 5 + 9 = 14The greatest number is 14, and the least number is -76. The difference is:14 - (-76) = 14 + 76 = 90Since this is not 72, n = 9 is not the correct value.Try n = 8:The three numbers in the set are:5 - n = 5 - 8 = -35 - n2 = 5 - 82 = 5 - 64 = -595 + n = 5 + 8 = 13The greatest number is 13, and the least number is -59. The difference is:13 - (-59) = 13 + 59 = 72This is the correct difference. Thus, the value of n is 8.
FILL BLANKLast year the value of one share of a stock increased by 10 percent during the first half of the year, and the value of one share of the stock increased by 50 percent during the entire year. What was the percent increase in the value of one share of the stock during the second half of the year?Give your answer to the nearest whole percent. (Enter your answer as an integer or a decimal in the answer box. Backspace to erase.)
In the first half of the year, the value of the stock increased by 10 percent. So, the value of the stock at the end of the first half of the year is:Value after first half = x + 0.10x = 1.10xThe value of the stock increased by 50 percent during the entire year, so the value of the stock at the end of the year is:Value after second half = x + 0.50x = 1.50xThe value at the end of the first half is 1.10x, and the value at the end of the year is 1.50x. The increase during the second half of the year is:Increase during second half = 1.50x - 1.10x = 0.40xThe percent increase during the second half of the year is:Rounding to the nearest whole percent, the percent increase in the value of one share of the stock during the second half of the year is 36 percent.
FILL BLANKThe width of rectangle R is of the length. If the area of R is 84, what is the perimeter of R? (Enter your answer as an integer or a decimal in the answer box. Backspace to erase.)
Let the length of rectangle R be L, and the width be W. We are told that:The area of the rectangle is given as 84, so:Area = L × W = 843L2 = 588L2 = 196The perimeter P of a rectangle is given by:P = 2L + 2WP = 2(14) + 2(6) = 28 + 12 = 40
FILL BLANKGreg's weekly salary is $187, which is 15 percent less than Karla's weekly salary. If Karla's weekly salary increases by 10 percent, by what percent must Greg's weekly salary increase in order to equal Karla's new weekly salary?Give your answer to the nearest tenth of a percent. (Enter your answer as an integer or a decimal in the answer box. Backspace to erase.)
Since Greg's salary is 15% less than Karla's salary, let Karla's original salary be K. This means:Greg's salary = Karla's salary - 15% of Karla's salary187 = K - 0.15K187 = 0.85KK = 220Karla's salary increases by 10%, so her new salary is:New Karla's salary = 220 + 10% of 220220 + (0.10 × 220) = 220 + 22 = 242Greg's salary must increase from 187 to 242. The percentage increase is:
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Q23: Fabric Admin is correct. Because Domain admin cannot create domains. Only Fabric Admin can among the given options. Q51: Wrapping @pipeline.parameter.param1 inside {} will return a string. But question requires the expression to return Int, so correct answer should be @pipeline.parameter.param1 (no {})
Question 62:
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Question 32:
Question 3:
Question 1:
date = sys.argv[1]
sys.argv[1]
date = spark.conf.get("date")
input()
date = dbutils.notebooks.getParam("date")
dbutils.notebook.run
Question 528:
Question 23:The correct answer is Domain admin (option B), not Fabric admin.
Question 2:For question 2, the key concept is the Longest Prefix Match. Routers pick the route whose subnet mask is the most specific (largest prefix length) that still matches the destination IP. From the options:
Question 129:Correct answer: CNAME
compute.osAdminLogin
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Question 2:
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