GMAT Section 2: Quantitative GMAT SECTION 2: QUANTITATIVE Dumps in PDF

Free GMAT GMAT SECTION 2: QUANTITATIVE Real Questions (page: 28)

To which of the following shapes the area can’t be calculated if the perimeter is given?

  1. Circle.
  2. An isosceles right triangle.
  3. Rectangle.
  4. A regular Hexagon.
  5. Square.

Answer(s): C

Explanation:

The perimeter of a rectangle is 2a + 2b. In order to calculate the area we need to know the multiplication of a x b.



A and B are two circles. The radius of A is twice as large as the diameter of B. What is the ratio between the areas of the circles?

  1. 1:8.
  2. 1:2.
  3. 1:4.
  4. 1:16.
  5. 1:6.

Answer(s): D

Explanation:

The radius of circle A is 4 times larger than the radius of circle B. The area of a circle is a function of the radius squared, therefore the area of radius A is 16 times bigger.



A, B, C, D and E are 5 consecutive points on a straight line. If BC = 2CD, DE = 4, AB = 5 and AC = 11, what is the length of AE?

  1. 21.
  2. 26.
  3. 30.
  4. 18.
  5. 16.

Answer(s): D

Explanation:

First, draw the line and the points.
In order to find the length of AE, find the length of CD and BC first. BC = AC – AB = 11 – 5 = 6.
BC = 2CD CD = 3.
AE = 5 + 6 + 3 + 4 = 18.



In a rectangular axis system, what is the distance between the following points: A(3,2) and B(7,5) ?

  1. 5.
  2. 7.
  3. 6.
  4. 4.
  5. 3.

Answer(s): A

Explanation:

First, draw a rectangular axis system and mark the two points.
The easiest way to find the distance between them is to draw a triangle, where the line AB is the hypotenuse.

You can see that the length of one side of the triangle is (5-2=3) and the other side is (7-3=4). The length of the line AB is received with the help
Of the Pythagoras principle: = 5.



In a rectangular axis system, what is approximate distance between the following points: C(1,2.5) and D (6.5,5.5) ?

  1. 5.5.
  2. 7.2.
  3. 6.3.
  4. 4.1.
  5. 3.8.

Answer(s): C

Explanation:

First, draw a rectangular axis system and mark the two points.
The easiest way to find the distance between them is to draw a triangle, where the line CD is the hypotenuse.
You can see that the length of one side of the triangle is
(5.5 - 2.5 = 3) and the other side is (6.5 – 1 = 5.5). The length of the line CD is received with the help Of the Pythagoras principle.



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