EC-Council Ethical Hacking and Countermeasures EC0-350 Dumps in PDF

Free EC-Council EC0-350 Real Questions (page: 28)

The follows is an email header. What address is that of the true originator of the message?
Return-Path: <bgates@microsoft.com>
Received: from smtp.com (fw.emumail.com [215.52.220.122].
by raq-221-181.ev1.net (8.10.2/8.10.2. with ESMTP id h78NIn404807
for <mikeg@thesolutionfirm.com>; Sat, 9 Aug 2003 18:18:50 -0500
Received: (qmail 12685 invoked from network.; 8 Aug 2003 23:25:25 -0000
Received: from ([19.25.19.10].
by smtp.com with SMTP
Received: from unknown (HELO CHRISLAPTOP. (168.150.84.123.
by localhost with SMTP; 8 Aug 2003 23:25:01 -0000
From: "Bill Gates" <bgates@microsoft.com>
To: "mikeg" <mikeg@thesolutionfirm.com>
Subject: We need your help!
Date: Fri, 8 Aug 2003 19:12:28 -0400
Message-ID: <51.32.123.21@CHRISLAPTOP>
MIME-Version: 1.0
Content-Type: multipart/mixed;
boundary="----=_NextPart_000_0052_01C35DE1.03202950"
X-Priority: 3 (Normal.
X-MSMail-Priority: Normal
X-Mailer: Microsoft Outlook, Build 10.0.2627
X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1165
Importance: Normal

  1. 19.25.19.10
  2. 51.32.123.21
  3. 168.150.84.123
  4. 215.52.220.122
  5. 8.10.2/8.10.2

Answer(s): C

Explanation:

Spoofing can be easily achieved by manipulating the "from" name field, however, it is much more difficult to hide the true source address. The "received from" IP address 168.150.84.123 is the true source of the



Buffer X is an Accounting application module for company can contain 200 characters. The programmer makes an assumption that 200 characters are more than enough. Because there were no proper boundary checks being conducted. Dave decided to insert 400 characters into the 200-character buffer which overflows the buffer. Below is the code snippet:
Void func (void)
{ int I; char buffer [200];
for (I=0; I<400; I++)
buffer (I)= ‘A’;
return;
}
How can you protect/fix the problem of your application as shown above? (Choose two)

  1. Because the counter starts with 0, we would stop when the counter is less then 200.
  2. Because the counter starts with 0, we would stop when the counter is more than 200.
  3. Add a separate statement to signify that if we have written 200 characters to the buffer, the stack should stop because it cannot hold any more data.
  4. Add a separate statement to signify that if we have written less than 200 characters to the buffer, the stack should stop because it cannot hold any more data.

Answer(s): A,C

Explanation:

I=199 would be the character number 200. The stack holds exact 200 characters so there is no need to stop before 200.



A Successfully Attack by a malicious hacker can divide into five phases, Match the order:

  1. The answer is Exhibit B.

Answer(s): A

Explanation:

• Reconnaissance refers to the preparatory phase where an attacker seeks to gather as much information as possible about a target of evaluation prior to launching an attack.
• In Second Phase Hacker starts to scan the remote host to gather information about OS using, Opened Ports etc.
• After gathering information about the remote hosts starts to gain access to remote host.
So, Reconnaissance refers to the preparatory phase where an attacker seeks to gather as much information as possible about a target of evaluation prior to launching an attack.



Which of the following is NOT a valid NetWare access level?

  1. Not Logged in
  2. Logged in
  3. Console Access
  4. Administrator

Answer(s): D

Explanation:

Administrator is an account not a access level.



Which of the following is NOT true of cryptography?

  1. Science of protecting information by encoding it into an unreadable format
  2. Method of storing and transmitting data in a form that only those it is intended for can read and process
  3. Most (if not all) algorithms can be broken by both technical and non-technical means
  4. An effective way of protecting sensitive information in storage but not in transit

Answer(s): D

Explanation:

Cryptography will protect data in both storage and in transit.



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