How long will it take for an initial deposit of $1,500 to grow to be $4,000, if the interest rate is 5% per year, compounded annually?
Answer(s): B
Either the $1,500 or the $4,000 must be entered as a negative number - it won't matter which. On the BAII Plus, press 5 I/Y, 1500 PV, 0 PMT, 4000 +/- FV, CPT N. On the HP12C, press 5 i, 2500 PV, 0 PMT, 4000 CHS FV,F. Note that the HP12C will indicate 21 years for the answer. Make sure the BAII Plus has the P/Y value set to 1.
Ball-Bearing, Inc. produces ball bearings automatically on a Kronar BBX machine. For one of the ball bearings, the mean diameter is set at 20mm. the standard deviation of the production over a long period of time was computer to be 0.150 mm. What percent of the ball bearings will have a diameter of 20.27 mm or more?
Answer(s): E
z = (x-u)/sigma = 20.27 - 20/0.15 = 1.8. from the z-table, z = 1.8 is 0.4641. So 1.0 - 0.9641 = 0.0359.
In an investment environment, an initial outlay of $100 grows to $156 in 7 years. The quarterly compounded rate of annual interest implicit in this is:
There are 28 quarters in 7 years. If the quarterly compounded rate is r, then we have 100*(1+r/4)^28 = 156, giving r = 6.4%
David's gasoline station offers 4 cents off per gallon if the customer pays in cash and does not use a credit card. Past evidence indicates that 40% of all customers pay in cash. During a one-hour period twenty-five customers buy gasoline at this station. What is the probability that at least ten pay in cash?
This is a binomial distribution: n!(p^r)(q^(n-r))/r!(n-r)!. n = 25, r = 10, p = 0.4 q = 0.6 P(10) = 25!(0.4^10)(0.6^15)/10!15! = 0.1612P(11) = 25!(0.4^11)(0.6^14)/11!14! = 0.1465P(12) = 25!(0.4^12)(0.6^13)/12!13! = 0.1140P(13) = 25!(0.4^13)(0.6^12)/13!12! = 0.0760P(14) = 25!(0.4^14)(0.6^11)/14!11! = 0.0434P(15) = 25!(0.4^15)(0.6^10)/15!10! = 0.0212P(16) = 25!(0.4^16)(0.6^9)/16!9! = 0.0088P(17) = 25!(0.4^17)(0.6^8)/17!8! = 0.0031Summing up we get close to 0.574.We can continue until r = 25 but the probability gets smaller and converges to 0.575.
Consider the following three investments:Future valueyearsinterest rate1.$50,000 89% per year2.$20,000 612% per year3.$35,000 37% per yearThe present values of the 3 investments are:
Answer(s): C
Future value = Present value*(1+r)^N for annual compounding. Therefore, Future valueyearsratePresent Value1.50,000 89% 50,000/(1.09)^8 = 25,0932.20,000 612% 20,000/(1.12)^6 = 10,1333.35,000 37% 35,000/(1.07)^3 = 28,570Note that the future value must always be greater than the present value.
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answer to this question "what administrative safeguards should be implemented to protect the collected data while in use by manasa and her product management team? " it should be (c) for the following reasons: this administrative safeguard involves controlling access to collected data by ensuring that only individuals who need the data for their job responsibilities have access to it. this helps minimize the risk of unauthorized access and potential misuse of sensitive information. while other options such as (a) documenting data flows and (b) conducting a privacy impact assessment (pia) are important steps in data protection, implementing a "need to know" access policy directly addresses the issue of protecting data while in use by limiting access to those who require it for legitimate purposes. (d) is not directly related to safeguarding data during use; it focuses on data transfers and location.
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question number 4s answer is 3, option c. i
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